200=1/2(5)t^2

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Solution for 200=1/2(5)t^2 equation: 


t in (-oo:+oo)

200 = 5*(1/2)*t^2 // - 5*(1/2)*t^2

200-(5*(1/2)*t^2) = 0

(-5/2)*t^2+200 = 0

-5/2*t^2 = -200 // : -5/2

t^2 = 80

t^2 = 80 // ^ 1/2

abs(t) = 4*5^(1/2)

t = 4*5^(1/2) or t = -(4*5^(1/2))

t in { 4*5^(1/2), -(4*5^(1/2)) }

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